About this opportunity
Aequor Healthcare lists this Travel PCU RN - $2,351 per week opportunity in johnstown, Pennsylvania. Review the employer’s description below for duties, qualifications and application requirements.
Job description
Aequor Healthcare is seeking a travel nurse RN PCU - Progressive Care Unit for a travel nursing job in Johnstown, Pennsylvania.
Job Description & RequirementsSpecialty: PCU - Progressive Care Unit
Discipline: RN
Start Date: 10/12/2026
Duration: 13 weeks
36 hours per week
Shift: 12 hours
Employment Type: Travel
All positions require at least two proven years experience
Aequor Healthcare Job ID . Pay package is based on 12 hour shifts and 36.0 hours per week (subject to confirmation) with tax-free stipend amount to be determined. Posted job title: Registered Nurse (RN) - PCU/Stepdown
About Aequor Healthcare Aequor Travel Nursing is a premiere healthcare staffing agency that specializes in placing healthcare travelers in short term contracts throughout the US.
Whether you're a seasoned healthcare professional looking for your next great adventure or just starting out and looking for your first big opportunity, Aequor has the inside track on the top jobs available in today's healthcare and clinical markets. At Aequor, our top priority is to be the best resource to help you connect with the perfect career opportunity and take the best care of you from the moment we first connect until your last shift is worked.
We pride ourselves on always offering top industry competitive pay. We have positions for nationwide covering every single state and ranging from 4 weeks - 26 weeks.
BenefitsWeekly pay
Holiday Pay
401k retirement plan
Referral bonus
Medical benefits
Dental benefits
Vision benefits
Worksite address
johnstown, PA, 15907, US
Who can apply
Review the original listing for work authorization, qualifications and employer requirements.